Given: parallelogram ABCD with AB = 2x, CD = 3y + 4, BC = x + 7, and AD = 2y. Find the lengths of the sides of the parallelogram.

AB = 58
CD = 58
BC = 36
AD = 36

Explain:

AB = CD
BC = AD
2x = 3y + 4 (1)
x + 7 = 2y (2)
From (1) and (2):
=> x = 29, y = 18
AB = 2x = 2*29 = 58
CD = 3y + 4 = 3*18 + 4 = 58
BC = x + 7 = 29 + 7 = 36
AD = 2*y = 2* 18 = 36

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