The distance between (-4,-5) and (4,2)

rida22 this is the third of these you asked for...

do you need help on the steps???

the solution is using the Pythagorean    theorem (a^2 + b^2 = c^2)

so distance "A" = x1-x2 which is 4 - (-4) in your problem = 8

"B" = y1-y2 = -5 - 2 = -7

64 + 49 = c^2

c^2 = 113

c =

Step-by-step explanation:

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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