Drag the equations to the correct locations on the table. Not all equations will be used. Determine which equation is parallel to line JK and which is perpendicular to line JK.

9514 1404 393

Step-by-step explanation:

The equation of the given line can be written as ...

  Δy·x -Δx·y = Δy·x1 -Δx·y1

where Δy and Δx are the differences in y and x coordinates of two points on the line, respectively. Here, we can find them to be ...

  Δy = 5-(-5) = 10

  Δx = -5 -1 = -6

Then the equation of the given line can be written as ...

  10x +6y = 10(-5) +6(5) = -20

Dividing by 2 puts this in standard form:

  5x +3y = -10 . . . . . . equation of the graphed line

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A parallel line will have the same x- and y-coefficients with a different constant. The equation of the parallel line is 5x +3y = 13.

A perpendicular line will have the x- and y-coefficients swapped, with one of them negated. The equation constant will likely be different. The coefficients may be multiplied by some factor so all the numbers are integers.

The equation of a perpendicular line is 6x -10y = 7.

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.