Eight soccer teams participate in a soccer tournament, so that each team plays with every other team exactly once. If one team wins against another, then the winning team gets two points, and the losing team gets zero points. If the two teams tie, then both teams get one point each. After the tournament, the teams are ranked by the total number points each team won. What is the minimum number of points a team must win, to ensure that it is in the top four teams

Step-by-step explanation:

With an eight team round robin, 28 games will be played in total (The total edges in K8). Since each game will produce two points regardless of outcome, 56 total points will be shared among the eight teams. In the absence of a well-defined tie breaking system, we assume that ties do not qualify as a guarantee. We define a team's point total as "ensuring" fourth place when the fifth place team could not possibly have that many points.

Ten points are not enough and eleven points must be enough. In one extreme case, teams A,B,C,D and E all draw each other and win against F,G, and H (who also draw each other), giving a fifth place team with ten points. If we have a fifth place team with eleven points then teams A,B,C,D, and E share at least 55 points, meaning teams F,G, and H share at most one point. However, F,G, and H play each other and must share at least six points, a contradiction. Therefore, 11 points guarantees fourth place at a minimum.

answer: 7270

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2