There are two numbers. The sum of 4 times the first number and 3 times the second number is 34 the difference between 2 times the first number and 3 times the second number is 12 . Find the two numbers​

10/9

23/3

Step-by-step explanation:

4x + 3y = 34

2x - 3y = 12

2x = 12 + 3y

2×(12 + 3y) + 3y = 34

24 + 6y + 3y = 34

24 + 9y = 34

9y = 10

y = 10/9

3×10/9 + 4x = 34

10/3 + 4x = 34

4x = (102 - 10)/3 = 92/3

x = (92/3)/4 = (92/3)/(4/1) = 92/(4×3) = 23/3