Assume 10% of Berkeley students are left-handed. If you are in a class of 50 people, what is the probability that exactly 4 of them are left-handed? Round your answer to the nearest hundredth, and omit the leading zero. Enter your answer here.

The answer is "0.18"

Step-by-step explanation:

If the probability exactly 4 were heft handed

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb