Find the area of the surface generated when the given curve is revolved about the y-axis. The part of the curve y=4x-1 between the points (1, 3) and (4, 15)

Step-by-step explanation:

Let take a look at the given function y = 4x - 1 whose point is located between (1,3) and (4,15) on the graph.

Here, the function of y is non-negative. Now, expressing y in terms of x in y = 4x- 1

4x = y + 1

By integration, the required surface area in the revolve is:

where;

g(y) =

∴

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation: