A committee that consists of five members are to be chosen from 6 boys and 5 girls. Find the number of different committees that can be formed if only two boys are selected​

150 different committees can be formed

Step-by-step explanation:

We have 6 boys and 5 girls and we want to select 5 members

Out of these 5 members, two boys are selected

Since two boys are selected, we are left with three girls

So, out of 6 boys, we select 2 boys and out of 5 girls, we select 3 girls

Mathematically, we know that the number of ways in which we can select r items from a total n follows the combinatorial formula;

nCr = n!/(n-r)!r!

With this, we have;

6C2 * 5C3

= (6!/(6-2)!2!) * (5!/(5-3)!3!) = 150 different committees can be formed

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.