Find the probability of rolling a three first and then a six when a pair of dice is rolled twice. a. 1/18
b. 5/648
c. 1/54
d. 5/324

5 / 648

Step-by-step explanation:

Given tbe sample space for a pair of dice attached below :

Sample space for a pair of dice = 6² = 36

Rolling a 3 first :

Recall, probability = required outcome / Total possible outcomes

P(rolling a 3). = 2 / 36 = 1 /18

Probability of rolling a 6 (second roll)

P(rolling a 6) = 5 / 36

Hence,

P(3) then P(6) ;

1 / 18 * 5/36 = 5 / 648

can i see the following ?

step-by-step explanation:

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2