The slope of diagonal OA is ? and its equation is ?

Slope =

Equation of the line →

Step-by-step explanation:

Let the equation of diagonal OA is,

y = mx + b

Here, m = Slope of the line OA

b = y-intercept

Slope of a line passing through two points and is given by,

m =

Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,

m =

m =

Since, line OA is passing through the origin, y-intercept will be 0.

Therefore, equation of OA will be,

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.