Please help me with this I'm submitting it tomorrow​

~ 30 cm^2

Step-by-step explanation:

area for rectangle (square is just rectangle with same length and width) = length × width

7cm × 7cm = 49cm^2

area for circle = pi×r^2 = pi×(d/2)^2

pi × ( 7cm / 2 )^2 = pi × (49cm^2 / 4) =

(22 / 7) × (49 / 4) cm^2 = (154 / 4) cm^2

((For area of half circle, just divide area of circle by 2))

Area_Square - Area_Half_Circle = Area_Remaining

49cm^2 - ((154 / 4)cm^2 ) / 2) = 49cm^2 - (77 / 4)cm^2

Area_Remaining = 29.75cm^2 --> ~30cm^2

answer: sorry but i need points

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet