Someone please help me with this math problem?

The length of the shortest side of the triangle is 10 units.

Step-by-step explanation:

Let a be the shortest side of the isosceles triangle and b be the two congruent sides.

The congruent sides b are each one unit longer than the shortest side. Hence:

The perimeter of the isosceles triangle is given by:

This is equivalent to the perimeter of a square whose side lengths are two units shorter than the shortest side of the triangle. Let the side length of the square be s. Hence:

The perimeter of the square is:

Since the two perimeters are equivalent:

Substitute for b:

Solve for a. Distribute:

Simplify:

Hence:

The length of the shortest side of the triangle is 10 units.

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