One jar holds 20 green marbles and 4 white marbles. A second jar holds 60 black marbles and 20 white marbles. What is the probability that a white marble will be drawn from both jars?

Step-by-step explanation:

Let RBY = “Draw a Red, then Blue, then Yellow”

● So all disjoint events we want to consider are: RBY,  

RYB, YRB, YBR, BYR, BRY – there are 6 of them.

● P(RBY) = P(R)*P(B)*P(Y) = (30/55)*(5/55)*(12/55)  

= .0108

● But we have 6 disjoint cases. Because each one is  

calculated as a product of the three, and each  

disjoint case has the same probability (each order is  

equally likely), our answer is 6*.0108 = .0649

5/20 so 25%

step-by-step explanation: