In the adjoining parallelogram ABCD, A is joined to any point E on BC. AE and DC produced meet at E Prove that. area of ∆BEF = area of ∆ CDE​

is there any photos or whatever?

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2