If the sin 60° is square root 3 over 2, then the cos ° = . (4 points) 30° ; 1 over 2 60° ; square root 2 over 2 30° ; square root 3 over 2 60° ; 1

Step-by-step explanation:

cos ² 60=1-sin² 60=1-(√3/2)²=1-3/4=(4-3)/4=1/4

cos 60=√(1/4)=1/2

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong