![\frac{15}{\sqrt{31} - 4}\\\\=\frac{15}{\sqrt{31} - 4} \times \frac{\sqrt{31} + 4}{\sqrt{31}+ 4} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ rationalizing \ the \ denominator \ ]\\\\=\frac{15( \sqrt{31} + 4 )}{(\sqrt{31})^2 - (4)^2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ (a-b)(a+b) = a^2 - b^2 \ ]\\\\=\frac{15 ( \sqrt{31} + 4)}{31 - 16}\\\\=\frac{15 (\sqrt{31} + 4)}{15}\\\\= \sqrt{31} + 4](/tpl/images/2418/7803/a973f.png)
15 / √31 - 4
can someone just solve this for me please
PLEASE ANSWER ONLY IF YOU ARE SURE els...
Mathematics, 05.07.2021 16:40 Sjanaya853
15 / √31 - 4
can someone just solve this for me please
PLEASE ANSWER ONLY IF YOU ARE SURE else I am out of the class
Answers: 3
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