What is the depth of water in a tank with 300,000 gallons of water at 70F when the pressure gauge at the bottom of the tank reads 23 psig?​

53.08 ft

Step-by-step explanation:

The pressure at the bottom of the tank, P = ρgh where ρ = density of water = 1000 kg/m³, g = acceleration due to gravity = 9.8 m/s² and h = depth of water in tank.

Since the pressure at the bottom of the tank, P = ρgh, making h subject of the formula, we have

h = P/ρg

Since P = 23 psig = 23 × 1 psig = 23 × 6894.76 Pa = 158579.48 Pa

Substituting the values of the other variables into h, we have

h = P/ρg

h = 158579.48 Pa/(1000 kg/m³ × 9.8 m/s²)

h = 158579.48 Pa/(9800 kg/m²s²)

h = 16.18 m

h = 16.18 × 1 m

h = 16.18 × 3.28 ft

h = 53.08 ft

it's 100

step-by-step explanation:

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

  n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the  14th  row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

read more on -