In how many ways can a sample of 6 keyboards be selected so that exactly two have an electrical defect

15ways

Step-by-step explanation:

This is a combination question since combination has to do with selection. Hence the number of ways sample of 6 keyboards can be selected so that exactly two have an electrical defect is expressed as;

6C2 = 6!/(6-2)!2!

6C2 = 6!/4!2!

6C2 = 6×5×4!/4!×2

6C2 = 6×5/2

6C2 = 30/2

6C2 = 15

Hence this can be done in 15ways

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )