Compute ×, where =−2+5, =2++3. (Write your solution using the standard basis vectors , , and . Use symbolic notation and fractions where needed.)

Given: =−2+5

and =2++3

To find: We need to find the value of ×

Solution: Here given,

=−2+5

and =2++3

Therefore, solving these two we have, =0

So,×=0

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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