Express the trigonometric ratios sinA in term of cosA​

To express the trigometric ration sinA in term of cosA

By using property of trignometry

\begin{gathered}sin^{2}{A}+cos^{2}{A}=1 < /p > < p > \\then \\ < /p > < p > sin{A}=\sqrt{1-cos^{2}{A} }\end{gathered}

sin

2

A+cos

2

A=1</p><p>

then

</p><p>sinA=

1−cos

2

A

there u go

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)