Y-2x-1=0 for -2 ≤ x ≤ 4 . can someone help me graph a straight line for this pls ?​

See the graph below.

It is a straight line segment with endpoints (-2,-3) and (4,9).

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Explanation:

We're told that x is between -2 and 4, including both endpoints.

Let's see what y is when we plug in x = -2

y-2x-1 = 0

y-2(-2)-1 = 0

y+4-1 = 0

y+3 = 0

y = -3

So x = -2 pairs up with y = -3. The point (x,y) = (-2,-3) is on the line. This is the left most endpoint.

Repeat for x = 4 to find what y must be

y-2x-1 = 0

y-2(4)-1 = 0

y-8-1 = 0

y-9 = 0

y = 9

Therefore the point (x,y) = (4,9) is also on the line. It's the right most endpoint

Once we have the two points, we can form the straight line. Simply connect the endpoints mentioned as shown below. We don't extend the line infinitely outwards in both directions because meaning x cannot be smaller than -2, and x cannot be greater than 4 either.

Side note: The given equation is the same as y = 2x+1. It has slope 2 and y intercept 1.

we'll this would mean that the dunk tank and the bounce house are the same for 20 hours because the 2 represents that the two activities, and the 20 represents the amount of hours they both are. so with this said, it means that the answer is c. the costs for a dunk tank and bounce house are the same for 20 hours.

c.the costs for a dunk tank and bounce house are the same for 20 hours.

hope this .

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c