The measures of two angles in a triangle are 32o and 78o. Which of the following equations could be used to find the measure of the third angle, x? (the ¨o¨ is a degree symbol)

180−32+78=x

180−32=x−78

180−(32+782÷2)=x

32+78+x=180

32+78+x=180

Step-by-step explanation:

All triangle angles add up to 180, so add 78 and 32 then subtract it from 180 to get x, which in another form is 32+78+x=180.

32 + 78 + x = 180

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 given angles and equate to 180, that is

32 + 78 + x = 180

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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