A projectile is fired straight up from ground level with an initial velocity of 112 ft/s. Its height, h, above the ground after t seconds is given by h = –16t2 + 112t. What is the interval of time during which the projectile's height exceeds 192 feet?

Step-by-step explanation:

We can do this the easy way and just set up an inequality and let the factoring do the work for us. The inequality will look like this:

We will move the constant over and get

and when you factor this you get that

3 < t < 4

Between 3 and 4 seconds is where the projectile reaches a height higher than 192 feet. With a little more work and some calculus you can find the max height to be 196 feet.

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step-by-step explanation: hope i you and who ever sees this answer have a great rest of your day : )

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