During the kickoff at a local high school football game, a football is placed onto a tee to a height of 0.125 feet above the ground. The football is kicked with an initial velocity of 80 feet per second. If the ball is caught at a height of 5 ft, approximately how long did it remain in the air? Round to the nearest hundredth of a second. Answer the question and make an equation

Time in air is 7.5 s.

Step-by-step explanation:

initial height, h = 0.125 feet

initial velocity, u = 80 ft/s

final height, h' = 5 ft

acceleration due to gravity, g = 32 ft/s^2

Let the time is t to reach the maximum height.

v = u - gt

0 = 80 - 32 t

t = 2.5 s

Let the time is t' from top to ground.

So the tie is 5 s

The time in air is

T = 2.5 + 5 = 7.5 s  

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this