Winning the jackpot in a particular lottery requires that you select the correct two numbers between 1 and 65 ​and, in a separate​ drawing, you must also select the correct single number between 1 and 60. Find the probability of winning the jackpot.

 1/ 233856 chance changed to 233856  x 2 = 467712

= 1 / 467712 chance as there are 2 drawings

Workings;

1 and 65 = 64

1 and 65 - 1 ball drawn = 63

1 and 60 -1 = 58

1/64 x 1/63 x 1/58 = 233856

1/4032 x 1/58 and to make these the same we 4038/58 =  69.62

then convert properly = 1/4032  x 69.62/4032 4032 x 4032 = 69.62/16257024 then 16257024/69.62 =233510.83

= 233511 chance if rounding before

1/ (233511 x 2) = 1/467022

Then one part is our actual probability

P) = 1/233856

But as they specified a special drawing

you need to repeat this as 64 x 63 x 58 x 2 as the last one cannot be in 1 drawing it has to be in 2nd drawing

233856  x 2 = 467712

= 1 / 467712 chance not rounding down before hand.

idk lol xd

step-by-step explanation:

ez do it yourself lazy