Help with these two and explain pls and thankyouuu

3-3x and 3

Step-by-step explanation:

f(x) = 3x-3

g(x) = -x

g(f(x)) in your g(x) substitute x with f(x)

g( f(x) ) = g( 3x-3) = -(3x-3) = -3x+3

is the the second choice from top because -3x+3 is the same with 3 -3x

g(f(x)) =3-3x

g(f(0)) always work from inside first, so first find f(0) than g(f(0))

f(0) = f(x=0) = 3*0-3 = -3

Now we do the g(f(0)) = g( -3) is the same as  

g(x) except that we substitute x for -3, g(x= -3) = -(-3) =3

g(f(0))=3

*an easier way to find the answer for the second problem would have been that we knew that f(g(x) ) = 3-3x so f(g(0)) =3-3*0 = 3

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58