At the city museum, child admission is 6.30 and adult admission is 9.50. On Saturday, three times as many adult tickets as child tickets were sold for total sales of $1113.60 . How many child tickets were sold that day?

There were 29 child's tickets sold that day.

Step-by-step explanation:

The first we need to do is assign variables to what our "unknowns" are. Let's say the number of adult tickets will be "A" and the number of child's tickets will be "C". We will use two equations to solve this problem

First, we know that each adult ticket is $8.90 and each child ticket is $5.30. When we add up the sales total for both types of tickets, the total sale is $928. We can represent this with the following equation:

$8.90A + $5.30C = $928

Next, we know that if we multiply the number of child's tickets by 3, we will get the number of adult tickets:

3 * C = A                                                                                                              Now, we can substitute 3 * C in for "A" in our first equation and solve:        8.9 (3C) + 5.3C = 928

26.7C + 5.3C = 928

32C = 928

C = 29

the given 6 = w/p is equivalent to 6p = w, where w is the total area of the walls and p is the area covered by a single can of paint.

knowing that 6 cans of paint will be needed, 6p = w becomes 6(6) = w = 36.   this tells us that the total area to be painted is 36 square units.

d is ur answer hopes this i dont really know how to explain it to u.