The distance between the lines: 4x+3y-11 and 8x+6y=15 is​

The distance between the lines: 4x+3y-11 and 8x+6y=15 is​

Step-by-step explanation:

You have two parallel and different lines. The form of the implicit equations is:

A*x + B*y + C= 0

A'*x + B'*y + C'=0

Since the two lines are parallel, the coefficients of their general equations must satisfy that the slopes are equal.

Therefore, the equations can be transformed so that the coefficients A and B are equal, multiplying or dividing one of them by a constant.

So, the distance between two lines can be expressed as follows:

In this case, you have:

Then, you have:

Replacing in the definition of distance:

Solving:

The distance between the lines: 4x+3y-11 and 8x+6y=15 is​

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation:

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9