How do I convert 345 from base 8 to binary and then hexadecimal?

(345)8 = (11100101)2

(11100101)2 =  E5

Step-by-step explanation:

Step 1: Look up each octal digit to obtain the equivalent group of three binary digits

(3)8 = (011)2

(4)8 = (100)2

(5)8 = (101)2

Step 2: Group each value of step 1 to make a binary number:  

011 100 101  

So, (11100101)2 is the binary equivalent to (345)8

Step 3: Converting the binary number to hexadecimal.

Write down the binary number:  

11100101

Step 4: Group all the digits in sets of four starting from the LSB (far right). Add zeros to the left of the last digit if there aren't enough digits to make a set of four:

1110 0101

Step 5: Use the table below to convert each set of three into an hexadecimal digit:

1110 = E, 0101 = 5

So, E5 is is the hexadecimal equivalent to the decimal number 11100101.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

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step-by-step explanation: