The sum of ages of two brothers A and B is 35 A is two thirds of B's age find their ages​

let the ages of the brothers be 2x and 3x

2x +3x=35

5x=35

x=35÷5

x=7

now,

A=2x=2×7=14

B=3x=3×7=21

this is the answer

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

i think it is 70

step-by-step explanation: