12.10.4 Test (CST): Income and Budgeting Question 12 of 25
What is the y-intercept of the line passing through the point 5.-6) with a
slope of - 1/7?
A.47/7
B.37/7
C.-37/7
D.-47/7

C.-37/7

Step-by-step explanation:

Given the following data;

Points (x, y) = (5, -6)

Slope, m = -1/7

Mathematically, the equation of a straight line is given by the formula;

y = mx + c

Where;

m is the slope.

x and y are the points

c is the intercept.

To find the y-intercept of the line, we would use the following formula;

y - y1 = m(x - x1)

y - (-6) = -⅐(x - 5)

y + 6 = -⅐x + 5/7

y = -⅐x + (5/7 - 6)

y = -⅐x - 37/7 = mx + c

Therefore, y-intercept (c) = -37/7

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐