There are three marbles in a bag. One is red and two are black. What is the probability of picking a red marble first, putting it back in the bag and then picking a black marble? Use the following probably need to find the answer.

The probability of picking a red marble first then replacing it and getting a black marble is 2/9. (The last option.)

Step-by-step explanation:

Hey there!

The probability of first getting a red marble is 1/3 since we have 1 red marble out of 2 + 1 = 3 total.

We put the marble back. The probability of then choosing a black marble is 2/3, since we have 2 black marbles out of 3 total.

So we get 1/3 * 2/3 = 2/9

The probability of picking a red marble first then replacing it and getting a black marble is 2/9. (The last option.)

Hope this helps, please mark brainliest if possible. Have a nice day. :)

addition

step-by-step explanation:

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: