A line passes through the point (4, -3) and has a slope of -3. Write an equation in slope-intercept form for this line.​

y=-3x+9

explanation

m=-3 (X1,Y1) = (4,-3)

(y-y1)= m×(x-x1)

(y-(-3))=-3(x-4)

y+3= -3x+12

y=-3x+12-3

y=-3x+9

okay wait before i answer, is this for your points on a graph?

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i