A circle P is circumscribed about a regular hexagon ABCDEF Arcs AB, BC, CD, DE, EF, FA are all equal
Select one:
a. False
b. True

True

Explanation:

Let point G be the center of both the hexagon and the circle.

The measure of arc AB is the same as central angle AGB, both of which are 360/6 = 60 degrees. This applies to the other arc measures as well. The full 360 degree circle is split up into 6 equal pieces, each piece being 60 degrees.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

alright so i think for this one it would to draw it out. this may be hard for me to try and draw, but i will do my best on here:

        r

  /       |     \

notice how it forms 2 triangles inside one bigger triangle.

so if we know the angle spr is the same as psr that is saying the measure of angle p is the same as angle s. this means the big triangle psr is either isosceles or equilateral. in both cases, the triangle is perfectly symmetrical when split down the middle, which is in this case rq. because we know it is perfectly symmetrical on both sides, we know that the two triangles inside the bigger one are equal.