`find the equatifindon of tangent and normal of parabola y²=16ax at point whose coordinate is -5a. ​

Step-by-step explanation:

we are given a equation of parabola and we want to find the equation of tangent and normal lines of the Parabola

finding the tangent line

equation of a line given by:

where:

to find m take derivative In both sides of the equation of parabola

divide both sides by 2y:

substitute the given value of y:

simplify:

therefore

now we need to figure out the x coordinate to do so we can use the Parabola equation

simplify:

we'll use point-slope form of linear equation to get the equation and to get so substitute what we got

simplify which yields:

finding the equation of the normal line

normal line has negative reciprocal slope of tangent line therefore

once again we'll use point-slope form of linear equation to get the equation and to get so substitute what we got

simplify which yields:

and we're done!

( please note that "a" can't be specified and for any value of "a" the equations fulfill the conditions)

In attachment

Step-by-step explanation:

For answer refer to attachment .

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

3x + 4y -25 =0 represents the amount of change sianna should recieve