A ping pong ball is released from a height of 60 centimeters (cm) and bounces to a height that is 3/4 the previous height. What function estimates the height, H, in cm of the ping pong ball after x bounces? Enter a number in each blank to correctly complete the function.

H = BLANK(BLANK)^x

H = 60(3/4)^x

Step-by-step explanation:

After each bounce, the height it reach is 3/4 the previous one.

Let the height of nth bounce be denoted as h_n and the first bounce is h_1.

We are given that h_1 = 60 cm. Following the rule in the problem, we get:

h_2 = (3/4)h_1 = (3/4)60

h_3 = (3/4)h_2 = (3/4)*(3/4)60 = 60(3/4)^2

h_4 = (3/4)h_3 = (3/4)*60(3/4)^2= 60(3/4)^3

We see that h_n = 60(3/4)^n is the formula for the height for the nth bounce. Therefore, H = 60(3/4)^x is the answer.

I hope this helps! :)

b

step-by-step explanation:

if a was wrong then it has to be b it cant be c either because not all the y intercepts are the same!

ok now , i would like brainlest plz

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116