A ball is thrown with an initial ve locity of 70 km per second, at an a ngle  of 35° with the horizontal. Find th e vertical and horizontal component s  of the velocity.                ​

i. The horizontal component of the ball = 15.8

ii. The vertical component of the ball = 11.2

Step-by-step explanation:

A thrown ball is an example of a projectile, whose motion can be explained with respect to both horizontal and vertical components.

Horizontal component of the ball = U Cos θ

Vertical component of the ball = U Sin θ

where U is the initial velocity of the ball, and θ is the angle of projection.

Thus for the given question,

U = 70 km/hr (19.44 m/s)

θ = 35°

So that;

i. The horizontal component of the ball = 19.44 Cos 35°

                                               = 19.44 x 0.8192

                                               = 15.785

The horizontal component of the ball = 15.8.

ii. The vertical component of the ball = 19.44 Sin 35°

                                                = 19.44 x 0.5736

                                                = 11.151

The vertical component of the ball = 11.2

i got 10.28 but that rounds up to 10.3