Graph the image of the figure using the transformation given.
reflection across y=-1​

I'm not graphing, but I can describe the reflection as R', S', T', U':

R' = (-3, 1)

S' = (-2, 0)

T' = (-1, 2)

U' = (-2, 2)

Step-by-step explanation:

y = -1 is the line one unit below the x axis (the x axis is y=0).

To reflect any point across y=-1, we just need to leave the x coordinate as was, but the (new y) will be -2-(old y)

R = (-3, -3), R' = (-3, -2+3) = (-3, 1)

S = (-2, -2), S' = (-2, -2+2) = (-2, 0)

T = (-1, -4), T' = (-1, -2+4) = (-1, 2)

U = (-2, -4), U' = (-2, -2+4) = (-2, 2)

yo answer should be 6 if im not mistaken

step-by-step explanation:

noncoplanar points are points that do not lie on the same line.