What is an equation of the line that passes through the point (8,-5) and is parallel to the line 5x + 4y = 24?

y=-5/4x+5

Step-by-step explanation:

Hi there!

We're given the line 5x+4y=24 and we want to find the line parallel to it that passes through (8,-5)

Parallel lines have the same slopes

First, we need to find the slope of 5x+4y=24.

We'll do that by converting 5x+4y=24 from standard form (ax+by=c where a, b, and c are integers) to slope-intercept form (y=mx+b where m is the slope and b is the y intercept)

subtract 5x from both sides

4y=-5x+24

divide by 4 on both sides

y=-5/4x+6

since -5/4 is in the place where m should be, it is the slope.

So the equation of the line parallel to it will also have -5/4 as the slope

Here's the equation so far in slope-intercept form:

y=-5/4x+b

we need to find b

because the equation will pass through (8,-5), we can use it to solve for b

substitute 8 as x and -5 as y

-5=-5/4(8)+b

multiply

-5=-10+b

add 10 to both sides

5=b

substitute 5 as b into the equation

y=-5/4x+5

That's the equation of the line parallel to 5x+4y=24.

Hope this helps!

idk

step-by-step explanation: