What are the coordinates of vertex A of square ABCD? Square A"B"C"D" is the final image after the rule T--10R 30+(x, y) was applied to square ABCD. Y 0 (-1,-6) 0 (-1, -2) 0 (-1, 6) 0 (-2, 1) 2 x -2 2 4 B" A" D​

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

step-by-step explanation:

infinity is the answer