Solve the radical equation. Which solution is extraneous? The solution x=-1 is an extraneous solution. Both x=-1 are x=-7 true solutions. The solution x=-7 is an extraneous solution. Neither x=-1 nor x=-7 is a true solution to the equation.

Both x = -1 and x = -7 are true solutions.

Step-by-step explanation:

Given

Required

Solve

Take square of both sides

Open bracket

Express as:

Expand

Factorize

Factor out x + 7

Solve:

So:

answer:   14

step-by-step explanation:          

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for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2