Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form? 7x + 2y = –1
7x + 2y = 1
14x + 4y = –1
14x + 4y = 1

7x + 2y = 1

Step-by-step explanation:

First we find the slope m of the line

The slope of a line that passes through 2 points x1, y1 and x2 , y2 is given as

m = (y2 - y1)/(x2 - x1)

Considering the points (–3, 11) and K(1, –3), the slope of the line m

= (-3-11)/(1 --3)

= -14/4

= 7/2

the line JK may be given as

y - 11 = -7/2(x - -3)

multiply through the equation by 2

2y - 22 = -7(x + 3)

2y - 22 = -7x - 21

7x + 2y = 22 - 21

7x + 2y = 1

15

step-by-step explanation:

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