Find the polynomial of minimum degree, with real coefficients, zeros at x=4+4i and x=2, and y-intercept at 64

Step-by-step explanation:

We want to find the minimum-degree polynomial with real coefficients and zeros at:

As well as a y-intercept of 64.

By the Complex Root Theorem, if a + bi is a root, then a - bi is also a root.

So, a third root will be 4 - 4i.

The factored form of a polynomial is given by:

Where a is the leading coefficient and p and q are the zeros. More factors can be added if necessary.

Substitute:

Since we want the minimum degree, we won't need to add any exponents.

Expand the second and third factors:

Hence:

Lastly, we need to determine a. Since the y-intercept is y = 64, this means that when x = 0, y = 64. Thus:

Solve for a:

Our factored polynomial is:

Finally, expand:

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0