Can someone assist me with this, has me mad drop menu 1:
A. y-axis
B. x-axis
C. line y=x
D. line y=-x
drop menu 2:
A. 4 units to the right and 10 units up
B. 8 units to the right and 4 units up
C. 10 units to the right and 2 units up
D. 10 units to the right and 4 units up​

A. y-axis

B. x-axis

C. line y=x

D. line y=-x

drop menu 2:

A. 4 units to the right and 10 units up

B. 8 units to the right and 4 units up

C. 10 units to the right and 2 units up

D. 10 units to the right and 4 units up​

C, and D

Step-by-step explanation:

First you reflect over the line y=x (line goes diagonal from quadrant I to quadrant III)

The rule of reflecting over the y=x line is that point (x,y) becomes point (y,x)

For example, point C ( -4, 2), becomes C' ( 2, -4)

Second is a translation 10 units to the right and 4 units up from C'(2,-4) to C''(0, 12)

divide by 5

step-by-step explanation:

60/5 = 12

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.