For one roadway section, the average number of cars passing a point is 2200 pcphpl (i. e. passenger cars per hour per lane). The cars travel at an average speed of 42 mph. What is the average distance (in feet) between common points (e. g. the front bumper) on successive cars in one lane

The average distance between common points on successive cars in one lane is of 100.8 feet.

Step-by-step explanation:

This question is solved by proportions, using a rule of three.

The cars travel at an average speed of 42 mph

Each mile has 5280 feet, so in 1 hour, the distance is of 42 miles = 221760 feet.

2200 pcphpl (i.e. passenger cars per hour per lane).

2200 cars in 221760 feet. Thus:

The average distance between common points on successive cars in one lane is of 100.8 feet.

-8

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)