Algebra Mary decided to travel from home to school which is 600 metres away. She started by walking “x” metres, then ran for twice the distance she walked. Mary then decided to take the bus for the rest of the journey which 65 metres more than the distance she ran. a) State an expression in terms of x for; i) the distance Mary ran [1 mark] ii) the distance Mary travelled by bus . [2 marks] iii) the total distance travelled [ 2 marks] b) Using the balancing method, solve the equation, hence state the distance Mary walked. [4 marks]

Step-by-step explanation:

Distance traveled by walking = x

i) The distance Mary run = 2 *x = 2x

ii) Distance traveled by bus = 65 m more than the distance she ran

                                             = 65 m more than 2x

Distance traveled by bus  = 2x + 65

Total distance traveled = 600 m

x + 2x + 2x +65 = 600

            5x + 65 = 600

                   5x = 600 - 65

                   5x = 535

                     x = 535/5

x = 107

Distance Mary walked = 107 m

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.