Lim x->1+( sin(1-x)-(e^(x-1))+1)/ lnx

We're given the one-sided limit,

Evaluating the limand directly at x = 1 gives the indeterminate from

(sin(1 - 1) - exp(1 - 1) + 1) / ln(1) = 0/0

so we can potentially solve the limit by applying L'Hopital's rule. Doing so gives

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

step-by-step explanation:

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