​$6300 is​ invested, part of it at 11​% and part of it at 6​%. For a certain​ year, the total yield is ​$533.00. How much was invested at each​ rate? $___ was invested at 11%

Invested at 11% : 3100

Invested at 6% : 3200

Step-by-step explanation:

let x= amount invested at 11%

let y= amount invested at 6%

we can write

Equation 1: x+y=6300

Equation2: .11x+.06y=533

Divide equation 2 by .06 to get

1.8333333x+y=8883.33333333

Subtract equation 2 from equation 1

.8333333x= 2583.33333333

x= 3100

Plug in x= 3100 into equation 1

3100+y= 6300

y= 3200

i believe that the slope of the line is -5

step-by-step explanation:

the answer is 1 becuz if it were 1.0 that would rip apart the entire so ya. : )

~potato.

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