A uniform rod of length 8m weighing 5kg is supported horizontally by two vertical parallel strings at P and Q at distances of 2m and 6m from one end. Weights of 1kg, 1.5 kg and 2kg are attached at distances of 1m, 5m and 7m respectively from the same end. Find the tension in each vertical string.​

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

i think it is 70

step-by-step explanation:

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

happy to

pls mark as brainliest

measurement of the swimming pool is given as = 7 yards 4.79 feet

first we will convert this to yards only.

1 foot = 0.33 yards

so, 4.79 feet = yards

so total yards are = yards

now we will convert this in meters.

1 yard = 0.914 meters

8.580 yards = meters

0.842 m = 0.842*100 = 84.2 cm

this becomes 7 meters and 84.2 cm

hence, the pool is 7 meters and 84.2 cm wide.