Triangle PQR has vertices P(-2, 6), Q(-8, 4) and R(1, -2). It is translated according to the rule (x, y)—> (x, - 2, y -16). What is the y-value of P’?

a. -18

b. -16

c. -12

d. -10

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To find this answer, you apply the given translation rule to the coordinates of point P(-2,6)

We see that point P' has a y coordinate of -10

This translation, aka shifting, rule moved point P 2 units to the left and 16 units down.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option